Question

If x=-2,y=3 and z=1, then the value of expression $x^3+y^3+z^3-3xyz$ is .

Answer 1

$x=-2,y=3,z=1$

$x^3+y^3+z^3-3xyz=(-2{)}^3+(3{)}^3+(1{)}^3-(3\times (-2)\times 3\times 1)=-8+27+1+18=38$