If $x = 2$ , $y = 3$ , then $x^{x} + y^{y}$ is equal to

30

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37

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33

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31

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Solution

The correct option is D $31$
Given $x = 2, y = 3$
$x^{x} + y^{y}$
$= 2^{2} + 3^{3} = 4 + 27 = 31$

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Similar questions

x = - 3

y = 2

x^{x}

y^{y}

x = 2

y = 3

[\frac{1}{x^{x}} + \frac{1}{y^{y}}]

x = 3

y = - 2

x^{x} + y^{y}

(y - z) (z + x) = 22

(z + x) (x - y) = 33

(x - y) (y - z) = 6

If x=2 and y=3, what is the value of $x^{x}$ + $y^{y}$ ?

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