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Question

If x20<3218, then the greatest possible integral value of 'x' is

A
22
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B
23
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C
24
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D
none of these
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Solution

The correct option is A 22
x20<3218=x20<290(32=25)
=(x1/9)180<(21/2)180
=x1/9<2x<29/2
=x<22.6
x=22
is option A is correct.


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