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Question

If x=2k+1 and y=k is a solution of the equation 5x+3y7=0, find the value of k.

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Solution

Given x=2k+1 and y=k is the solution of equation 5x+3y-7=0
5x+3y7=0
Put the value of x=2k+1 and y=k we get
5(2k+1)+3(k)7=0
10k+5+3k7=0
13k2=0
13k=2
k=213

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