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Question

If x2r occurs in (x+2x2)n, then n2r must be of the form

A
3k
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B
3k1
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C
3k+1
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D
4k±1
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Solution

The correct option is B 3k
Writing the general term
Tk+1=nCrxn3k2k
For x2r
n3k=2r
n2r=3k
Where K is a positive integer 0

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