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Point of Inflection

if x =2t-3t^2...

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if x =2t-3t^2 and y=6t^3 then dy/dx at point (-1,6) is

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Similar questions

x = a sin 2 t (1 + cos 2 t)

y = b cos 2 t (1 - cos 2 t)

\frac{d y}{d x}

t = \frac{π}{4}

.

x = a sin 2 t (1 + cos 2 t)

y = b cos 2 t (1 + cos 2 t)

\frac{d y}{d x}

t = \frac{π}{4}

.

x = sin t, y = cos 2 t

\frac{d y}{d x} =

x = \frac{2 t}{1 + t^{2}}

y = \frac{1 - t^{2}}{1 + t^{2}}

\frac{d y}{d x}

t = 2

Q. If the normal to the curve

x = t - 1, y = 3 t^{2} - 6

(1, 6)

makes intercepts

a

b

x

y -

axis respectively, then the value

a + 12 b

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Point of Inflection

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