If x2 x-3-90 and 7 y-1-2-2 y-1-2-y1-2x- and y are positive numbers- then what is the value of x2-y2 -

The correct option is C 1172x^2+3x 90=0 2x^2+15x 12x 90=0 x(2x+15) 6(2x+15)=0 ∴ = 15/2 or 6 7/√(y)+2/√(y)=√(y) 7+2=y ⇒ y = 9 x^2+y^2 = nbsp;6^2 +9^2 = 36 + ...

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Quantitative Aptitude

Quadratic Equations

If x2 x+3=90 ...

Question

If x (2x+3) = 90 and $7 y^{- (\frac{1}{2})} + 2 y^{- (\frac{1}{2})} = y^{(\frac{1}{2})}$ (x and y are positive numbers), then what is the value of $x^{2}$ + $y^{2}$ ?

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117

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Solution

The correct option is C 117
2 $x^{2}$ +3x-90=0
2 $x^{2}$ +15x-12x-90=0
x(2x+15)-6(2x+15)=0
$∴$ = - $\frac{15}{2}$ or 6
$\frac{7}{\sqrt{y}} + \frac{2}{\sqrt{y}} = \sqrt{y}$
7+2=y $\Rightarrow$ y = 9
$x^{2}$ + $y^{2}$ = $6^{2}$ + $9^{2}$ = 36 + 81 = 117

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If x (2x+3) = 90 and 7y−(12)+2y−(12)=y(12) (x and y are positive numbers), then what is the value of x2+ y2?

The correct option is C 1172x2+3x-90=0 2x2+15x-12x-90=0 x(2x+15)-6(2x+15)=0 ∴ = - 152 or 6 7√y+2√y=√y 7+2=y ⇒ y = 9 x2+y2 = 62 +92 = 36 + 81 = 117

If x (2x+3) = 90 and $7 y^{- (\frac{1}{2})} + 2 y^{- (\frac{1}{2})} = y^{(\frac{1}{2})}$ (x and y are positive numbers), then what is the value of $x^{2}$ + $y^{2}$ ?

The correct option is C 117
2 $x^{2}$ +3x-90=0
2 $x^{2}$ +15x-12x-90=0
x(2x+15)-6(2x+15)=0
$∴$ = - $\frac{15}{2}$ or 6
$\frac{7}{\sqrt{y}} + \frac{2}{\sqrt{y}} = \sqrt{y}$
7+2=y $\Rightarrow$ y = 9
$x^{2}$ + $y^{2}$ = $6^{2}$ + $9^{2}$ = 36 + 81 = 117