If x + 2y – 3 =0 and x – 2y – 5 = 0 are the diameters of a circle. The coordinates of the center of the circle is

(4,-1/2)

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(2,1/2)

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(3,-1/2)

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(4,1/2)

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(5,1/2)

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Solution

The correct option is A
(4,-1/2)

Given x + 2y - 3 =0 and x - 2y - 5 = 0 are the diameters of the circle.

The center of the circle will be the point of intersection of the two lines.

Solving the two equations we get the center of the circle as (4, - $\frac{1}{2}$ ).

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If x + 2y – 3 =0 and x – 2y – 5 = 0 are the diameters of a circle. The coordinates of the center of the circle is

The correct option is A (4,-1/2) Given x + 2y - 3 =0 and x - 2y - 5 = 0 are the diameters of the circle. The center of the circle will be the point of intersection of the two lines. Solving the two equations we get the center of the circle as (4, - 12).

The correct option is A
(4,-1/2)

Given x + 2y - 3 =0 and x - 2y - 5 = 0 are the diameters of the circle.

The center of the circle will be the point of intersection of the two lines.

Solving the two equations we get the center of the circle as (4, - $\frac{1}{2}$ ).