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Question

If x = 3-2√2, find √x+1/ √x

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Solution

(a-b)^2=a^2-2ab+b^2
X=3-2root2

(Root2-1)^2=(root2)^2-2(root2)(1)+(1)^2
(Root2-1)^2=2-2root2+1
= (2+1)-2root2
=3-2 root2
When x=(root2-1)^2
So root take both sides we get
Root x=(root2-1)

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