If x=3+2√2,thenthevalueof(√x+1√x) is:
1
2
2√2
8
-1
(√x+1√x)2=x+1x+2=(3+2√2)+1(3+2√2)+2=(3+2√2)+1(3+2√2)×(3−2√2)(3−2√2)+2=(3+2√2)+(3−2√2)+2=8.∴(√x+1√x)=2√2
If x = √2+√1, then the value of [x+1x] is ?
If x=√3+1√3−1andy=√3−1√3+1,thenthevalueof(x2+y2)is:
If p = x 1/3 + x −1/3 , then p3 - 3p is equal to