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Question

If x=3+313+323, then find the value of x39x2+18x.

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Solution

x=3+31/3+32/3
(x3)=31/3+32/3
C0 be on both sides
x3273(x)(3)(x3)
=3+9+3(3)1/3(3)2/3(x3)
x3279x+27x
=12+(3)(3)(x3)
x3279x+27x=12+9x27
x39x+18x=12

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