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Question

If (x3−3x2−x+3) is divided by (x-1) we get ax2−bx+c, then value of (a+b+c)


A

-4

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B

-3

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C

-2

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D

-1

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Solution

The correct option is A

-4


When (x33x2x+3) is divided by (x-1) we get the quotient as x22x3 and 0 as remainder. So, taking the coefficients of a, b, and c= 1 - 2 - 3 = - 4


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