If x -3-4- - 2- then x belongs to A- -5- -1- -B- RC- - D- -5- -

The correct option is B ℝ||x 3|+4|≥2 ⇒|x 3|+4≤ 2 or |x 3|+4≥2 ⇒|x 3|≤ 6 (not possible) or |x 3|≥ 2 (always) For any real value of x, |x 3|≥0 So, x∈ℝ ...

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Byju's Answer

Standard XI

Mathematics

Disjoint

If x -3|+4| ≥...

Question

If $| | x - 3 | + 4 | \geq 2$ , then $x$ belongs to

ϕ

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[- 5, \infty)

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(- \infty, - 5] \cup [1, \infty)

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R

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Solution

The correct option is D $R$
$| | x - 3 | + 4 | \geq 2$
$\Rightarrow | x - 3 | + 4 \leq - 2$ or $| x - 3 | + 4 \geq 2$
$\Rightarrow | x - 3 | \leq - 6$ (not possible)
or $| x - 3 | \geq - 2$ (always)
For any real value of $x$ , $| x - 3 | \geq 0$
So, $x \in R$

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If ||x−3|+4|≥2, then x belongs to

The correct option is D R||x−3|+4|≥2 ⇒|x−3|+4≤−2 or |x−3|+4≥2 ⇒|x−3|≤−6 (not possible) or |x−3|≥−2 (always) For any real value of x, |x−3|≥0 So, x∈R

If $| | x - 3 | + 4 | \geq 2$ , then $x$ belongs to

The correct option is D $R$
$| | x - 3 | + 4 | \geq 2$
$\Rightarrow | x - 3 | + 4 \leq - 2$ or $| x - 3 | + 4 \geq 2$
$\Rightarrow | x - 3 | \leq - 6$ (not possible)
or $| x - 3 | \geq - 2$ (always)
For any real value of $x$ , $| x - 3 | \geq 0$
So, $x \in R$