If $(x + 3, 4 - y) = (1, 7)$ , then $(x - 3, 4 + y)$ is equal to

(- 2, - 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- 5, 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(3, 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(- 5, 1)$
$(x + 3, 4 - y) = (1, 7) \Rightarrow x + 3 = 1, 4 - y = 7$
$\Rightarrow x = 1 - 3 = - 2, y = 4 - 7 = - 3$
$∴ (x - 3, 4 + y) = (- 2 - 3, 4 - 3) = (- 5, 1)$ .

Suggest Corrections

Similar questions

If $x^{2} + y^{2} = 25, x y = 12$ ,then complete set of $x =$

U = {3, 4, 5, 6, 7, 8, 9}, X = {3, 4}, Y = {5, 6}

Z = {7, 8, 9}

Y^{'} \cap {(X \cap Z)}^{'}

x + y = 3, 4 x - 3 y = 26 .

The tangent to the curve $x^{2} + y^{2} = 25$ parallel to the line 3x-4y=7 exist at the point

cos (4 y - 3 x - 2) - cos (4 y + 3 x + 2) = 2 + 2 ln (k^{4} - 255)

cos (4 y - 3 x - 2) + cos (4 y + 3 x + 2) = 2 k + 8

(x, y)

k

Join BYJU'S Learning Program