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Zeroes of a Polynomial

If x3+5 x2+10...

Question

If $x^{3}$ + 5 $x^{2}$ + 10 k leaves remainder –2x when divided by $x^{2}$ + 2, then the value of k is

-2

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-1

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Solution

The correct option is C
1

On actually dividing $x^{3}$ + 5 $x^{2}$ + 10k by ( $x^{2}$ + 2), the remainder obtained is – 2x + 10k – 10.

Therefore –2x + 10k – 10 = – 2x or k = 1.

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