Question

If $x^3+6x^2+4x+k$ is exactly divisible by $(x+2)$, then the value of k is -

• A. –6
• B. –7
• C. –8
• D. –10

Answer 1

The correct option is D

–10

Since $(x+2)$ is a factor, so $x=-2$ will make it zero.

∴ ${(-2)}^3+6{(-2)}^2+2(-2)+k=0$

or k = -12