If x-3-8- find the value of x 2-1 x 2

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Concept of Inequality

If x=3+8, fin...

Question

If x = 3+ $\sqrt{8}$ , find the value of $x^{2} + \frac{1}{x^{2}}$

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x = (3 + \sqrt{8})

(x^{2} + \frac{1}{x^{2}})

\frac{1}{x}

x^{2} + \frac{1}{x^{2}}

x = 3 + \sqrt{8}

x^{2} - \frac{1}{x^{2}}

x - \frac{1}{x} = 3,

x^{2} + \frac{1}{x^{2}}

x^{4} + \frac{1}{x^{4}} .

x = 3 - 2 \sqrt{2}

\frac{1}{x}

x + \frac{1}{x}

x - \frac{1}{x}

\sqrt{x} + \frac{1}{\sqrt{x}}

\sqrt{x} - \frac{1}{\sqrt{x}}

x^{2} + \frac{1}{x^{2}}

x^{2} - \frac{1}{x^{2}}

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