If (x, 3) and (3, 5) are the extremities of a diameter of a circle with centre at (2, y), then the values of x and y are
x=8,y=2
None of these
The end points of the diameter of a circle are (x, 3) and (3, 5).
According to the question, we have :
x+32=2,y=5+32
⇒x=1,y=4