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If x, 3 and 3...

Question

If (x,3) and (3,5) are the ends of the diameter of a circle with centre at (2,y) then (x,y) is

A

(1,4)

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B

(4,1)

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C

(8,2)

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D

(2,8)

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Solution

The correct option is A
(1,4)

A(x,3)
B(3,5)
C $(\frac{x + 3}{2}, 4)$
$= \frac{x + 3}{2} = 2$
$x = 1$
$y = 4$
$(x, y) = (1, 4)$

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