If x - 3 and y - - 2- then the value of xy - yx is -7p-9- So- p is-

Given, x=3 and y= 2 #160; x^y + y^x =3^ 2+( 2)^3 =19+( 8) =1 729 = 719 = 789 ...

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Logarithmic Function

If x = 3 an...

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If $x = 3$ and $y = - 2$ , then the value of $x^{y} + y^{x}$ is $- 7 \frac{p}{9}$ . So, $p$ is:

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x = 3

y = - 2

x^{y} + y^{x}

- 7 \frac{8}{9}

(i) x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2}) (i i) x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

x y + y x = - 1 (x, y \neq 0)

x^{3} - y^{3}

2 x + y = 3

x y = 1

(x + y)^{x - y}

x^{y} = y^{x}

{(\frac{x}{y})}^{\frac{x}{y}}

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