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Question

If x=3 and y=5, find the value of 8x312x2y+6xy28y3.


A

900

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B

650

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C

874

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D

749

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Solution

The correct option is C

874


Observe the given expression carefully it is similiar to the expansion of the identity (ab)3, i.e.,

8x312x2y+6xy28y3=(2x)3y37y33×(2x)2×y+3×2x×y2=(2xy)37y3

Now, it is very easy to put the values of x and y in (2xy)37y3

(2xy)37y3=(2×35)37×53

=17×125=874


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