If x=3 and y=5, find the value of 8x3−12x2y+6xy2−8y3.
−874
Observe the given expression carefully it is similiar to the expansion of the identity (a−b)3, i.e.,
8x3−12x2y+6xy2−8y3=(2x)3−y3−7y3−3×(2x)2×y+3×2x×y2=(2x−y)3−7y3
Now, it is very easy to put the values of x and y in (2x−y)3−7y3
⇒(2x−y)3−7y3=(2×3−5)3−7×53
=1−7×125=−874