wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If x=3 and y=5, find the value of 8x312x2y+6xy28y3.


A

900

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

650

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

874

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

749

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

874


Observe the given expression carefully it is similiar to the expansion of the identity (ab)3, i.e.,

8x312x2y+6xy28y3=(2x)3y37y33×(2x)2×y+3×2x×y2=(2xy)37y3

Now, it is very easy to put the values of x and y in (2xy)37y3

(2xy)37y3=(2×35)37×53

=17×125=874


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identity (a-b)³
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon