If x3-1x3- 14- then x-1x -

The correct option is A 2 (x+(1/x))^3=>x^3+3x^2(1/x^2) (1/x^3) =(x^3 (1/x^3)) 3(x (1/x)) >let>x (1/x)=t then>t^3+3t 14=0>o ...

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Integration by Partial Fractions

If x3-1x3= ...

Question

If $x^{3} - \frac{1}{x^{3}} = 14$ , then $x - \frac{1}{x} =$

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Similar questions

$I f x^{3} - \frac{1}{x^{3}} = 14, t h e n x + \frac{1}{x}$ =

x - \frac{1}{x} = 2

x^{3} - \frac{1}{x^{3}}

x + \frac{1}{x} = 4

x^{3} + \frac{1}{x^{3}}

x = \frac{5 - \sqrt{21}}{2}

(x^{3} + \frac{1}{x^{3}}) - 5 (x^{2} + \frac{1}{x^{2}}) + (x + \frac{1}{x}) =

If $(x + \frac{1}{x}) = 4$ , find the value of

(1) $(x^{3} + \frac{1}{x^{3}})$

(2) $(x - \frac{1}{x})$

(3) $(x^{3} - \frac{1}{x^{3}})$

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