If $x^{3} + k x^{2} + m x + 10 = (x + 1) (x - 2) (x - 5)$ then find the values of k and m.

Open in App

Solution

Given $x^{3} + k x^{2} + m x + 10 = (x + 1) (x - 2) (x - 5)$ on solving RHS simultaneously.
$x^{3} + k x^{2} + m x + 10 = (x + 1) (x^{2} - 7 x + 10)$
$x^{3} + k x^{2} + m x + 10 = x^{3} - 6 x^{2} + 3 x + 10$
on comparing LHS & RHS
we get [k=-6] and [m=3]
$∴ [k = - 6]$ and $[m = 3]$

Suggest Corrections

Similar questions

k

x - k

x^{3} - k x^{2} + 2 x + k + 4

k

x - 3

k^{2} x^{3} - k x^{2} + 3 k x - k

x - 2

k x^{2} - \sqrt{2} x + 1

k

x^{5} + K x^{2}

(x - 1) (x - 2) (x - 3)

x^{2}

K

k

x - 2

p (x) = x^{3} + k x^{2} + 12 x - 8

Join BYJU'S Learning Program