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Question

If x3+kx2+mx+10=(x+1)(x2)(x5) then find the values of k and m.

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Solution

Given x3+kx2+mx+10=(x+1)(x2)(x5) on solving RHS simultaneously.
x3+kx2+mx+10=(x+1)(x27x+10)
x3+kx2+mx+10=x36x2+3x+10
on comparing LHS & RHS
we get [k=-6] and [m=3]
[k=6] and [m=3]

1199713_1380379_ans_860e9683720a4f27a1c54a9f17a5ee42.JPG

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