If x=3√2+2√3, find x+1x .
21√2+10√36
Given x = 3√2+2√3.
∴ 1x = 13√2+2√3
Rationalising factor of 3√2+2√3
= 3√2−2√3
Multiplying both numerator and denominator by 3√2−2√3 , we get
(3√2−2√3)(3√2+2√3)×(3√2−2√3)
= 3√2−2√332√(2)2−22√(3)2
= 3√2−2√318−12
So, 1x = 3√2−2√36
x+1x = 3√2+2√3 + 3√2−2√36
= 18√2+12√3+3√2−2√36
= 21√2+10√36