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Algebraic Identities

If x=3+√8, ...

Question

If $x = 3 + \sqrt{8}$ , then $x^{4} + \frac{1}{x^{4}}$ is

A

1056

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B

1158

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C

1156

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D

1154

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Solution

The correct option is C $1154$
$x = 3 + \sqrt{8}$
$\frac{1}{x} = 3 - \sqrt{8}$
$x + \frac{1}{x} = 6$
$x^{2} + \frac{1}{x^{2}} = 34$
$x^{4} + \frac{1}{x^{4}} = 1154$

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Similar questions

x = 3 + \sqrt{8}

, then find the value of

x^{4} + \frac{1}{x^{4}}

x - \frac{1}{x} = 8

, then find the value of

x^{4} + \frac{1}{x^{4}}

x + \frac{1}{x} = 3

x^{4} + \frac{1}{x^{4}}

=

x = 3 + \sqrt{8}

find the value of

x^{4} + \frac{1}{x^{4}}

If such that f(2) = 0, then f(x) is

(A) (B)

(C) (D)

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