If $x = 3 - y^{2}$ and $y = - 2$ , find the value of $x$ .

-2

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-1

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Solution

The correct option is B -1
Given equations are $x = 3 - y^{2}$ and $y = - 2$
Putting the value of $y$ in first equation, t
$\Rightarrow x = 3 - {(- 2)}^{2} \Rightarrow x = 3 - 4 = - 1$

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If x=3−y2 and y=−2, find the value of x.

The correct option is B -1Given equations are x=3−y2 and y=−2Putting the value of y in first equation, t⇒x=3−(−2)2⇒x=3−4=−1

If $x = 3 - y^{2}$ and $y = - 2$ , find the value of $x$ .

The correct option is B -1
Given equations are $x = 3 - y^{2}$ and $y = - 2$
Putting the value of $y$ in first equation, t
$\Rightarrow x = 3 - {(- 2)}^{2} \Rightarrow x = 3 - 4 = - 1$