Question

If x=3, y=2 and z=-1 then the value of $\left(\frac{x^3+y^3+1}{y^3-z^3}\right)$ is,

• A. 4
• B. 1
• C. -2
• D. 0

Answer 1

The correct option is A 4

x=3,y=2,z=-1 then

$\frac{x^3+y^3+1}{y^3-z^3}$

After putting the value

$\Rightarrow \frac{3^3+2^3+1}{2^3-(-1^3)}$

$\Rightarrow \frac{27+8+1}{8+1}$

$\Rightarrow \frac{36}{9}=4$