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Question

If x=(3y2+4y+3), then xdy will be

A
3y2+4y+3+C
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B
3y2+8y+3+C
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C
y3+2y2+3y+C
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D
3y3+4y+6+C
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Solution

The correct option is C y3+2y2+3y+C
Given x=3y2+4y+3
Then xdy=(3y2+4y+3)dy=y3+2y2+3y+C

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