Question

If $|x+3y|=5$ and $|y|=4$ x and y are real numbers. Which of the following can be possible value of x.

• A. - 1 or - 12
• B. - 7 or 17
• C. - 7 or -17
• D. 10 or 12

Answer 1

The correct option is C - 7 or -17

$|y|=4$ For y = 4, we get $|x+12|=5$ therefore $x+12=5$ or $-x-12=5$
Therefore $x=-7$ or $x=-17$

For y = -4
$|x-12|=5$
Therefore
$x-12=5$ or $-x+12=5$
$x=17$ or $x=7$
The correct answer is option C.