Question

If x + 3y = 6 and 2x - 3y = 12, then the value of $(x-y{)}^2$ is:

• A. 16
• B. 25
• C. 36
• D. 49

Answer 1

The correct option is C 36

Given: x + 3y = 6...(i) and 2x - 3y = 12...(ii)
$\left(i\right)\Rightarrow x=6-3y...\left(iii\right)$
Thus, (ii) $\Rightarrow 2(6-3y)-3y=12$
$\Rightarrow 12-6y-3y=12$
$\Rightarrow y=0$
Thus, (iii) $\Rightarrow x=6$

Hence, $(x-y{)}^2=6^2=36$