If $(x - 4)^{2} = x^{2} - 8 x + c$ is an identity, then $c =$

4

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16

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8

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Solution

The correct option is B $16$
Given: $(x - 4)^{2} = x^{2} - 8 x + c$ is an identity.
$\Rightarrow x^{2} - 8 x + 16 = x^{2} - 8 x + c \Rightarrow c = 16$

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