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Byju's Answer
Standard XII
Mathematics
Theorems for Continuity
If x+4| y | =...
Question
I
f
x
+
4
|
y
|
=
6
, then
y
as a function of
x
is
A
c
o
n
t
i
n
u
o
u
s
a
t
x
=
0
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B
Derivable
x
=
0
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C
d
y
d
x
=
1
2
f
o
r
a
l
l
x
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D
None of these
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Solution
The correct options are
A
c
o
n
t
i
n
u
o
u
s
a
t
x
=
0
B
Derivable
x
=
0
x
+
4
|
y
|
=
6
first draw the graph,
1
s
t
take
y
as positive and then as negative we get.
|
y
|
=
6
−
4
4
⇒
so, the line is non continuous and non-differentiable only at
x
=
0
(
i
)
continuous at
x
=
0
(
2
)
Derivable at
z
=
0
(
3
)
\dfrac {dy}{dx}=\dfrac {1}{2}
f
o
r
x\times (x \neq 6)$
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0
Similar questions
Q.
If
y
=
f
(
x
)
is a derivable function of
x
such that the inverse function
x
=
f
−
1
(
y
)
is defined.
then show that
d
x
d
y
=
1
(
d
y
d
x
)
1
where
d
y
d
x
≠
0
Q.
If
x
4
+
y
4
−
a
2
x
y
=
0
defines
y
implicitly as function of
x
, then
d
y
d
x
=
Q.
For each of the differential equations, find the general solution:
1.
d
y
d
x
=
1
−
cos
x
1
+
cos
x
2.
d
y
d
x
=
√
4
−
y
2
(
−
2
<
y
<
2
)
3.
d
y
d
x
=
1
(
y
≠
1
)
4.
sec
2
x
tan
y
d
x
+
sec
2
y
tan
x
d
y
=
0
5.
(
e
x
+
e
−
x
)
d
y
−
(
e
x
−
e
−
x
)
d
x
=
0
6.
d
y
d
x
=
(
1
+
x
2
)
(
1
+
y
2
)
7.
y
log
y
d
x
−
x
d
y
=
0
8.
x
4
d
y
d
x
=
−
y
5
9.
d
y
d
x
=
sin
−
1
x
10.
e
x
tan
y
d
x
+
(
1
−
e
x
)
sec
2
y
d
y
=
0
Q.
If
y
=
(
1
+
x
)
(
1
+
x
2
)
(
1
+
x
4
)
⋯
(
1
+
x
2
n
)
then
d
y
d
x
at x = 0 is
Q.
If
d
y
d
x
=1+x+y+xy and y(-1)=0, then function y is
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