If x4 occurs in the r th term in the expansion of x 4-1- x 316- then r -A- 7B- 8C- 10D- 9

The correct option is D 9 T_r = ^16 C _r 1 (x^4)^16 r(1/x^3)^r 1 = ^16 C _r 1x^67 7r → 67 7r=4 → r=9 ...

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General Term of Binomial Expansion

If x4 occurs ...

Question

If $x^{4}$ occurs in the $r^{t h}$ term in the expansion of $(x^{4} + \frac{1}{x^{3}})^{16}$ , then r =

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