If x4 occurs in the rth term in the expansion of (x4+1x3)15, then r =
7
8
9
10
Tr = 15Cr−1 (x4)16−r(1x3)r−1 = 15Cr−1x67−7r\\
→67−7r=4→r=9
If in the expansion of (x4−1x3)15,x−17 occurs in rth term, then
If x4 occurs in the rth term in the expansion of (x4+1x3)16, then r =
If the coefficients of rth term and (r+4)th term are equal in the expansion of (1+x)20, then the value of r will be