If x < 4 , x^2 < 16 and x is a natural number. Prove that there are only three values which satisfy all the given equations simultaneously.

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Solution

Natural numbers are numbers 1,2,3....
for first equation x<4 the natural numbers satisfying this equation is 1,2 and 3
now for the second equation x^2 < 16
the solution of the given equation is -4<x<4 the natural numbers including in this are 1,2&3
so
there are only three values which satisfy all the given equations

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