Question

If $x=5$ is a root of equation $k{x}^2-14x-5=0$, then find the value of $k$

Answer 1

Given,

$x=5$ is one of the root of the equation $k{x}^2-14x-5=0$

then, it should satisfy the equation,

$k(5{)}^2-14(5)-5=0$

$\Rightarrow k=\frac{14\left(5\right)+5}{5^2}$

$\therefore k=\frac{75}{25}=3$