If X-8n-7 n -1 - n - N and Y -49 n -1 - n - N - thenA- x - YB- x - YC- Y - xD- x - Y

The correct option is B 8^n 7n 1 = (7+1)^n 7n 1 =(^nC_2 nbsp;7^2+^nC_3 7^3+...+^nC_n 7^n) =49(^nC_2+^nC_37+...+^nC_n7^n 2) For n≥2 =49(Integer) ∴ X⊂Y ...

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Byju's Answer

Standard XI

Mathematics

Subset

if X=8n-7 n -...

Question

if X = {$8^n-7n-1/n \in N$} and Y = {$49(n-1)/n \in N$}, then

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Solution

The correct option is A

$8^{n} - 7 n - 1$ = $(7 + 1)^{n} - 7 n - 1$

=( $^{n} C_{2} 7^{2} +^{n} C_{3} 7^{3} + . . . +^{n} C_{n} 7^{n}$ )

=49( $^{n} C_{2} +^{n} C_{3} 7 + . . . +^{n} C_{n} 7^{n - 2}$ )

For n $\geq$ 2

=49(Integer) $∴$ X $\subset$ Y

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if X = {\(8^n-7n-1/n \in N\)} and Y = {\(49(n-1)/n \in N\)}, then

The correct option is A 8n−7n−1 = (7+1)n−7n−1 =(nC272+nC373+...+nCn7n) =49(nC2+nC37+...+nCn7n−2) For n≥2 =49(Integer) ∴ X⊂Y

The correct option is A

$8^{n} - 7 n - 1$ = $(7 + 1)^{n} - 7 n - 1$

=( $^{n} C_{2} 7^{2} +^{n} C_{3} 7^{3} + . . . +^{n} C_{n} 7^{n}$ )

=49( $^{n} C_{2} +^{n} C_{3} 7 + . . . +^{n} C_{n} 7^{n - 2}$ )

For n $\geq$ 2

=49(Integer) $∴$ X $\subset$ Y