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Question

If x=945, find x21x2 and x31x3

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Solution

x=9451x=9+45(945)(9+45)=9+45

x1x=85x+1x=18

Now, x21x2=(x1x)(x+1x)=1445

and x31x3=(x1x)(x2+1x2+x.1x)=85[(x1x)22+1]=85[3201]=83195=25525

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