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Question

If x=9 is a chord of contact of the hyperbola x2y2=9, the the equation of the tangent at one of the points of contact is

A
x+3y+2=0
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B
3x22y3=0
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C
3x2y+6=0
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D
x3y+2=0
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Solution

The correct option is B 3x22y3=0
x=9 is chord of cortact
Of x2y2=9 ...(1)
Put x=9 in rquation (1)
81y2=9
y2=72y=±62
So, one of the point of contact is (9,62)
tangent at 9,62 is
x,x1a2yy1b2=1
x×9y×62=9
3x22y=3

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