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Question

If x=997, y=998, z=999, then the value of x2+y2+z2−xy−yz−zx will be:

A
3
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B
9
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C
16
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D
4
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Solution

The correct option is D 3
Clearly y=x+1;z=x+2
So, we have to find:
x2+(x+1)2+(x+2)2x(x+1)(x+1)(x+2)x(x+2)
=> x2+x2+2+2x+x2+4+4xx2xx22xx2x22x
=> 3


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