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Standard XII

Mathematics

Property 7

If x=aa>0 div...

Question

If x = a (a > 0) divides the area bounded by x axis, part of $x^{2} (y - 1) = 8$ and the ordinates x = 2, x = 4 into two equal parts then a _____

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Solution

The correct option is B

$\int_{2}^{a} (1 + 8 ∖_{x^{2}}) d x = 2 {(x - 8 ∖ x)}_{2}^{a} = 2 a - \frac{8}{a} + 2 = 2 a = \sqrt{8}$

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If x = a (a > 0) divides the area bounded by x axis, part of x2(y–1)=8and the ordinates x = 2, x = 4 into two equal parts then a _____

The correct option is B ∫a2(1+8∖x2)dx=2(x−8∖x)a2=2a−8a+2=2a=√8

If x = a (a > 0) divides the area bounded by x axis, part of $x^{2} (y - 1) = 8$ and the ordinates x = 2, x = 4 into two equal parts then a _____

The correct option is B

$\int_{2}^{a} (1 + 8 ∖_{x^{2}}) d x = 2 {(x - 8 ∖ x)}_{2}^{a} = 2 a - \frac{8}{a} + 2 = 2 a = \sqrt{8}$