Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A−1 Given, x=acos4θ and y=asin4θ On differentiating with respect to θ respectively, we get dxdθ=4acos3θ(−sinθ) =−4asinθcos3θ and dydθ=4asin3θcosθ ∴dydx=dydθdxdθ=4asin3θcosθ−4asinθcos3θ ⇒dydx=−sin2θcos2θ=−tan2θ Now, (dydx)θ=3π4=−tan2(3π4)=−1