Question

If x + a is a factor of $x^4-a^2{x}^2$ + 3x -6a, then a =

• A. 0
• B. - 1
• C. 1
• D. 2

Answer 1

The correct option is A

0

x + a is a factor of f(x) = $x^4-a^2{x}^2$ + 3x -6a

Let x + a = 0, then x =-a

Now, f(-a) $=(-a{)}^4-a^2(-a{)}^2+3(-a)-6a$

=$a^4-a^4-3a-6a=-9a$

$\therefore$ Remainder = 0

$\therefore$ -9a= 0 $\Rightarrow$ a = 0