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Question

If x=asinθ+bcosθ,y=acosθ+bsinθ, then show that (ax+by)2+(bxay)2=(a2+b2)2.

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Solution

Given,
x=asinθ+bcosθ,y=acosθ+bsinθ
Now,
(ax+by)=(a2+b2)sinθ.......(1).
Again (bxay)=(b2+a2)cosθ.......(2).
Now,
(ax+by)2+(bxay)2=(a2+b2)2(sin2θ+cos2θ)
or, (ax+by)2+(bxay)2=(a2+b2)2

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