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Byju's Answer
Standard X
Mathematics
Relation between Trigonometric Ratios
If x = a si...
Question
If
x
=
a
sin
θ
+
b
cos
θ
,
y
=
−
a
cos
θ
+
b
sin
θ
, then show that
(
a
x
+
b
y
)
2
+
(
b
x
−
a
y
)
2
=
(
a
2
+
b
2
)
2
.
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Solution
Given,
x
=
a
sin
θ
+
b
cos
θ
,
y
=
−
a
cos
θ
+
b
sin
θ
Now,
(
a
x
+
b
y
)
=
(
a
2
+
b
2
)
sin
θ
.......(1).
Again
(
b
x
−
a
y
)
=
(
b
2
+
a
2
)
cos
θ
.......(2).
Now,
(
a
x
+
b
y
)
2
+
(
b
x
−
a
y
)
2
=
(
a
2
+
b
2
)
2
(
sin
2
θ
+
cos
2
θ
)
or,
(
a
x
+
b
y
)
2
+
(
b
x
−
a
y
)
2
=
(
a
2
+
b
2
)
2
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