If x=asinθ+ccosθ and y=acosθ−csinθ, then x2+y2=a2+c2.
A
True
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B
False
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Solution
The correct option is A True x2+y2=(asinθ+ccosθ)2+(acosθ−csinθ)2=a2sin2θ+c2cos2θ+2acsinθcosθ+a2cos2θ+c2sin2θ−2acsinθcosθ=a2(sin2θ+cos2θ)+c2(sin2θ+cos2θ)=a2+c2