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B
abc
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C
a + b + c
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D
3abc
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Solution
The correct option is D 3abc xa×xb×xc=1 ⇒xa+b+c=1=x0 ⇒a+b+c=0
Now since a3+b3+c3−3abc =(a+b+c)(a2+b2+c2−ab−bc−ac) ⇒a3+b3+c3−3abc=0 ∴a3+b3+c3=3abc
Hence , (d) is the right choice.