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Question

If (x+a)(x+b)(x+c)=x310x2+45x15 find (a+b+c).

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Solution

(x+a)(x+b)(x+c)=x310x2+45x15
=(x2+(a+b)x+ab)(x+c)
=x3+cx2+(a+b)x2+(a+b)cx+abx+abc
=x3+x2(a+b+c)+x(ac+bc+ab)+abc
on compairing a+b+c=10
(a+b+c)=10

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