If x - a- y - b- z - c-2- where - is a complex cube root of unity- then x-a - y-b - z-c -

If $ω$ is a complex cube root of unity, then the value of $\frac{a + b ω + c ω^{2}}{c + a ω + b ω^{2}}$ + $\frac{a + b ω + c ω^{2}}{b + c ω + b ω^{2}}$ is :

Q. Let

ω

being cube root of unity. Also let,

x = a + b ω + c ω^{2}, y = a ω + b ω^{2} + c, z = a ω^{2} + b + c ω

. Find the value of

\frac{x^{2}}{y z} + \frac{y^{2}}{z x} + \frac{z^{2}}{x y}

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If x=a,y=bω,z=cω2, where ω is a complex cube root of unity, then xa+yb+zc=

The correct option is C 0Given that x=a,y=bω,z=cω2Then xa+yb+zc=aa+bωb+cω2c=1+ω+ω2=0

If $x = a, y = b ω, z = c ω^{2}$ , where $ω$ is a complex cube root of unity, then $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} =$

The correct option is C 0
Given that $x = a, y = b ω, z = c ω^{2}$
Then $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = \frac{a}{a} + \frac{b ω}{b} + \frac{c ω^{2}}{c}$
$= 1 + ω + ω^{2} = 0$