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Question

If x=a,y=bω,z=cω2, where ω is a complex cube root of unity, then xa+yb+zc=

A
3
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B
1
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C
0
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D
none of these
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Solution

The correct option is C 0
Given that x=a,y=bω,z=cω2
Then xa+yb+zc=aa+bωb+cω2c
=1+ω+ω2=0

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