If $x$ and $R$ stands for distance, then which of the following is dimensionally same as $\int \frac{R d x}{x^{2}}$ ?

- \frac{R^{2}}{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

R x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{R}{x}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 R x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{R}{x}$
Given, $\int \frac{R d x}{x^{2}}$
$\Rightarrow [\int \frac{R d x}{x^{2}}] = \frac{[R] [x]}{[x^{2}]} = \frac{[R]}{[x]}$

Suggest Corrections

Similar questions

x

R

\int \frac{R d x}{x^{2}}

\int \frac{d x}{\sqrt{a^{2} - x^{2}}} = \frac{1}{a} \sin^{- 1} \frac{a}{x}

Let x and a stand for distance. Is $\int \frac{d x}{\sqrt{a^{2} - x^{2}}} = \frac{1}{a} s i n^{- 1} \frac{a}{x}$ dimensionally correct ?

x

a

\int \frac{d x}{\sqrt{a^{2} - x^{2}}} = \frac{1}{a} {sin}^{- 1} \frac{a}{x}

\int \frac{d x}{\sqrt{a^{2} - x^{n}}} = s i n^{- 1} \frac{x}{a}

Join BYJU'S Learning Program